Customise Consent Preferences

We use cookies to help you navigate efficiently and perform certain functions. You will find detailed information about all cookies under each consent category below.

The cookies that are categorised as "Necessary" are stored on your browser as they are essential for enabling the basic functionalities of the site. ... 

Always Active

Necessary cookies are required to enable the basic features of this site, such as providing secure log-in or adjusting your consent preferences. These cookies do not store any personally identifiable data.

Functional cookies help perform certain functionalities like sharing the content of the website on social media platforms, collecting feedback, and other third-party features.

Analytical cookies are used to understand how visitors interact with the website. These cookies help provide information on metrics such as the number of visitors, bounce rate, traffic source, etc.

Advertisement cookies are used to provide visitors with customised advertisements based on the pages you visited previously and to analyse the effectiveness of the ad campaigns.

Other cookies are those that are being identified and have not been classified into any category as yet.

The quadratic formula

The quadratic formula

What is the quadratic formula?

Despite being a useful skill, it does take quite a bit of time to factorise an expression, then set each bracket to 0 and find the correct value of the unknown. This can be avoided if we make use of the quadratic formula which will be given to you in your exam. This formula will give the correct value for given any coefficients and is shown below:

The quadratic formula

Since the equation will be given to you in your exam you will not need to learn it completely but just how to use it.

There are three different stages that you must apply when using the formula:

1) Identify the values of ab and c.

2) Substitute these values into the formula and find the correct value for x.

3) Decide how many decimal places your answer should be given to.

Obviously, it will be easier if we split the formula up and work out smaller parts, as the entire thing is quite long to type into a calculator. As well as this it is worth noting that the use of \pm will give us two possible results for x.

Example

Use the quadratic formula to find the value of the unknown value in the following equations:

1) 3x^2+7x+3=0

2) 4x^2+15x+10=0

3) -x^2+x+\frac{1}{3}=0

1) Here we can allocate the values of a, b and c as 3, 7 and 3 respectively. Putting these into the quadratic formula we get x=\frac{-7 \pm\sqrt{(7^2-4(3)(3))}}{2(3)} which is then worked out on a calculator to find the values of x as -0.566 or -1.768.

2) Here we do the same process and find ab and c as 4, 15 and 10. Inserting into the equation gives an answer of -0.867 or -2.883 to 3dp.

3) Now we have the values as 1, -1 and \frac{1}{3} which gives us an answer of x=1.264 or -0.264

One easier way to think of the quadratic formula is to split it up into two separate parts. So

x=\frac{-b \pm\sqrt{(b^2-4ac)}}{2a}

Becomes

x=\frac{-b}{2a} \pm\frac{\sqrt{(b^2-4ac)}}{2a}

By splitting the denominator and writing this as above it becomes easier to work out two different parts and then work out one solution for x by adding the two, and the other solution by taking one from the other.

Note that the quadratic formula only works for equations up to x^2 and is not used for any higher powers than 2.

online gcse courses

Looking to get a GCSE?

We offer a wide range of GCSE courses.

Learn more